The displacement equations of two waves are g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The amplitude of the first wave $y_1 = 10 \sin(3\pi t + \pi/3)$ is $A_1 = 10$.For the second wave,$y_2 = 5 \sin 3\pi t + 5\sqrt{3} \cos 3\pi t$. T

Vedclass · Accepted Answer

$1 : 1$

Vedclass · Answer

(C) The amplitude of the first wave $y_1 = 10 \sin(3\pi t + \pi/3)$ is $A_1 = 10$.For the second wave,$y_2 = 5 \sin 3\pi t + 5\sqrt{3} \cos 3\pi t$. This is of the form $y = a \sin \omega t + b \cos \omega t$,where the amplitude $A_2 = \sqrt{a^2 + b^2}$.Here,$a = 5$ and $b = 5\sqrt{3}$.$A_2 = \sqrt{5^2 + (5\sqrt{3})^2} = \sqrt{25 + 75} = \sqrt{100} = 10$.The ratio of their amplitudes is $\frac{A_1}{A_2} = \frac{10}{10} = 1:1$.

The displacement equations of two waves are given as $y_1 = 10 \sin(3\pi t + \pi/3)$ and $y_2 = 5(\sin 3\pi t + \sqrt{3} \cos 3\pi t)$. What is the ratio of their amplitudes?

Similar Questions

The endosperm of gymnosperms is $...$

Which of the following plants exhibits a haplontic life cycle?

If $\frac{1}{x(x^2 + 1)} = \frac{A}{x} + \frac{Bx + C}{x^2 + 1}$,then $(A, B, C) = $

Let $A = \{1, 2, 3, 4, 5\}$ and $B = \{2, 3, 6, 7\}$. Then the number of elements in $(A \times B) \cap (B \times A)$ is:

Which of the following is paramagnetic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module